Which ordered pair is a solution to the inequality 3x - 4y < 16 ?

Mathematics

1 answer:

fgiga [73]2 years ago

4 0

Answer:

Step-by-step explanation:

You are given 3x-4y<16 and we want to see which of the ordered pairs is a solution.

These ordered pairs are assumed to be in the form (x,y).

A. (0,-4) ?

3x-4y<16 with (x=0,y=-4)

3(0)-4(-4)<16

0+16<16

16<16 is not true so (0,-4) is not a solution of the given inequality.

B. (4,-1)?

3x-4y<16 with (x=4,y=-1)

3(4)-4(-1)<16

12+4<16

16<16 is not true so (4,-1) is not a solution of the given inequality.

C. (-3,-3)?

3x-4y<16 with (x=-3,y=-3)

3(-3)-4(-3)<16

-9+12<16

3<16 is true so (-3,-3) is a solution to the given inequality.

D. (2,-3)?

3x-4y<16 with (x=2,y=-3)

3(2)-4(-3)<16

6+12<16

18<16 is false so (2,-3) is not a solution to the given inequality.

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2(2x-3) + 3(x + 1) = 5x +2

Lerok [7]

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5 0

2 years ago

Read 2 more answers

Please help! :))

denis23 [38]

Answer:

Check below

Step-by-step explanation:

Hi,

We're dealing with linear functions. $f(x)=mx+b$

We have here the first function.

$g(x)=3x$

That's a linear function, with slope, and no linear coefficient since

But on the other hand, the functions below, they all describe parallel lines, since their slope has the same value. I've changed the letters to make it easier the comprehension.

Even though each one has the same slope value, they have different non zero linear coefficients, {-6,-18,6,18}. Unlike, the first one

$h(x)=3(9x-2) \rightarrow h(x)= 27x-6\\i(x)=9(3x-2)\rightarrow i(x)=27x-18\\j(x)=3(9x+2)\rightarrow j(x)=27x+6 \\k(x)=9(3x+2)\rightarrow k(x)=27x+18\\$