Answer:
A,D and E are the answers.
mark brainliest
Answer:
$1000 ; 500 ; 1000 ; y = 500x + 1000
Step-by-step explanation:
From the graph, the initial deposit which started the savings account is $1000 ; this is the value on the y - intercept, the value in the account at time or period = 0.
The slope :
x1 = 0 ; y1 = 1000
x2 = 6 ; y2 = 4000
Slope = Rise / Run
Rise = y2 - y1 = 4000 - 1000 = 3000
Run = x2 - x1 = 6 - 0 = 6
Hence,
Slope = 3000 / 6
Slope = 500
y - intercept = 1000 (from. Graph)
Equation in slope intercept form:
General form : y = mx + c
m = slope ; c = intercept
Equation is written as ;
y = 500x + 1000
For 11, we start by plugging 1 in, getting 2(1)^2+1-5=-2=y
Plugging 1+m instead, we get 2(1+m)^2+1+m-5=2(1+2m+m^2)+1+m-5
= 2+4m+2m^2+1+m-5= 2m^2+5m-2. We have to find the difference between that and -2, so 2m^2+5m-2 -(-2)=2m^2+5m
Differentiating 12, we use the Power Rule to get -6x^2+14, and plugging x=1 into it, we get -6(1)^2+14=-6+14=18
To stretch or shrink the graph in the y direction, multiply or divide the output by a constant. 2f (x) is stretched in the y direction by a factor of 2, and f (x) is shrunk in the y direction by a factor of 2 (or stretched by a factor of ). Here are the graphs of y = f (x), y = 2f (x), and y = x.
y is f(x) btw.
