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3 years ago

Which ordered pair is a solution to the inequality 3x - 4y < 16 ?

Mathematics

1 answer:

fgiga [73]3 years ago

4 0

Answer:

Step-by-step explanation:

You are given 3x-4y<16 and we want to see which of the ordered pairs is a solution.

These ordered pairs are assumed to be in the form (x,y).

A. (0,-4) ?

3x-4y<16 with (x=0,y=-4)

3(0)-4(-4)<16

0+16<16

16<16 is not true so (0,-4) is not a solution of the given inequality.

B. (4,-1)?

3x-4y<16 with (x=4,y=-1)

3(4)-4(-1)<16

12+4<16

16<16 is not true so (4,-1) is not a solution of the given inequality.

C. (-3,-3)?

3x-4y<16 with (x=-3,y=-3)

3(-3)-4(-3)<16

-9+12<16

3<16 is true so (-3,-3) is a solution to the given inequality.

D. (2,-3)?

3x-4y<16 with (x=2,y=-3)

3(2)-4(-3)<16

6+12<16

18<16 is false so (2,-3) is not a solution to the given inequality.

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Solve the quadratic equation 6x^2-13x-28=0 by factoring.

mixer [17]

First step to factor the trinomial, multiply the constant -28 with the leading coefficient 6.

So, -28 * 6 = - 168.

Next step is to breakdown -168 into two multiples so that their addition will result the coefficient of w= - 13.

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So, next step is to replace -13x with -21x + 8. Therefore,

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3x (2x - 7) + 4 (2x - 7) = 0 Take out the common factor from each group.

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3 years ago

Equivalent to 3n + 2(1 - 4n)

kirill115 [55]

Answer:

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Step-by-step explanation:

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