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3 years ago

Differentiation. questions 1 and 2

Mathematics

1 answer:

drek231 [11]3 years ago

4 0

For 11, we start by plugging 1 in, getting 2(1)^2+1-5=-2=y

Plugging 1+m instead, we get 2(1+m)^2+1+m-5=2(1+2m+m^2)+1+m-5
= 2+4m+2m^2+1+m-5= 2m^2+5m-2. We have to find the difference between that and -2, so 2m^2+5m-2 -(-2)=2m^2+5m

Differentiating 12, we use the Power Rule to get -6x^2+14, and plugging x=1 into it, we get -6(1)^2+14=-6+14=18

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What is the pattern with these letters<br> J, F, M, A, M

klemol [59]

Answer:

The pattern is:

Step-by-step explanation:

they are the first letters of each month in the year -

J - January

F- Febuary

M - March

A - April

M - May

Continuing...

J - June

J - July

A - August

S - September

O - October

N - November

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2 years ago

PEASE HELP ME 70 POINTS

scZoUnD [109]

Answer:

x: -2

f(x): 1.5

x: 0

f(x): 0.5

x: 3

f(x): -1

Step-by-step explanation:

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2 years ago

Read 2 more answers

Y=x2<br> x=-3 -2 -1 0 1 2 3<br> y=

brilliants [131]

Answer:

see below

Step-by-step explanation:

Y=x^2

x=-3 -2 -1 0 1 2 3

y=(-3)^2 (-2)^2 (-1)^2 0^2 1^2 2^2 3^2

9 4 1 0 1 4 9

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3 years ago

The decimal expansion of all rationals will be

aleksklad [387]

Answer:

I'm pretty sure they either terminate after so many digits (end) or repeat a certain pattern of numbers.

Step-by-step explanation:

The first will look like this: 432.2340

The second would look like this: 324.234234234... ("234" would keep repeating over and over and over. And can be any sequence of #'s)

^Random numbers were used as examples^

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2 years ago

The United States is about the only country that still uses the units feet, miles, and gallons. However, you might see some car

Black_prince [1.1K]

Answer: $4.5 \text{ miles per gallon}$

Step-by-step explanation:

Given : The fuel efficiency of car = 7.6 km per kilogram

We also given that

1 mile = 1.609 km

Then, $\text{1 km}=\dfrac{1}{0.609}\text{ mile}$

1 gallon = 3.785 liters

$\text{1 liter}=\dfrac{1}{3.785}\text{ gallon}$

1 liter of gasoline = 0.729 kg

Then, $\text{1 kg}=\dfrac{1}{0.729}\text{ liter}$

$\Rightarrow\ \text{1 kg}=\dfrac{1}{0.729}\times\dfrac{1}{3.785}\text{gallon}$

Now, the fuel efficiency of car will be :

$7.6\times\dfrac{1}{0.729}\times\dfrac{1}{3.785}\times\dfrac{1}{0.609}\\\\=4.52275317827\approx4.5 \text{ miles per gallon}$

Hence, the car’s fuel efficiency in miles per gallon= 4.5

3 0

2 years ago