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2 years ago

If h(x) = 3x and k(x) = 2x - 4, what is h(k(x))??

Mathematics

1 answer:

charle [14.2K]2 years ago

5 0

Answer:

Step-by-step explanation:

k(x) = 2x - 4 = 0

2x = 4

x = 2

Now replacing it in h(x) as 2

h(x) = 3x

3 × 2 = 6

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A housepainter mixed 5 gal of blue paint with every 9 gal of yellow paint in order to make a green paint. What is

ella [17]

Answer:

Step-by-step explanation:

5:9 is the original ratio.

we know that anything times 5 would have the ones place of either 5 or 0 so we can eliminate c and d. Then we test out the other two choices.

25/5=5

45/9=5

A is correct.

15/5=3

45/9=5

Option B is incorrect.

so, the ratio is 25:45

The answer is A!

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3 years ago

-1<9+n<17 i don't understand how to solve it

Ugo [173]

-1<9+n<17

-1-9<n<17-9

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6 0

3 years ago

There are three monomials such that the greatest common factor of the first and second monomials is 2xy, and the greatest common

sveta [45]

The gratest comon factor is 2

5 0

2 years ago

Can anybody please help solving this problem?

pantera1 [17]

Area of the shaded region = Area of a square - Area of a circle

Side of a square = 2r
Area of a square = (2r)² = 4r²

Area of a circle = πr²

Area of the shaded region = 4r² - πr² = r²(4-π)

7 0

3 years ago

Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ

const2013 [10]

Answer:

$\frac{(2a + 1)^2}{50a}$

Step-by-step explanation:

Given

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$

Required

Find the equivalent

We start by changing the / to *

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$

$\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}$

Factorize 10a - 5

$\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}$

Expand 4a² - 1

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}$

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}$

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: $a^2- b^2= (a+b)(a-b)$

The expression becomes

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}$

Combine both fractions to form a single fraction

$\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}$

Divide the numerator and denominator by 2a - 1

$\frac{(2a + 1)((2a + 1)}{5*10a}$

Simplify the numerator

$\frac{(2a + 1)^2}{5*10a}$

$\frac{(2a + 1)^2}{50a}$

Hence,

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$ = $\frac{(2a + 1)^2}{50a}$

4 0

3 years ago