Answer:
10
Step-by-step explanation:
idk how to explain it but the answer is 10
Write a recursive formula for these sequences<br><br>
3,6,18,72,360,...<br><br><br>
5,9,18,34,59,...
Temka [501]
1) A(n+1)=2×A(n) where n1 = 3 and n greater than or equal to 1
Sorry I don't get the second one
Answer:
Step-by-step explanation:
Exponential growth function:
The exponential growth function for a population, after t years, is given by:
In which P(0) is the initial population and r is the growth rate.
A warren of rabbits has a population of 350. The population is increasing at a rate of 3% per year.
This means that 
So
How can you write an exponential growth function to find the monthly growth rate?
Monthly growth rate means that the time is divided by 12(as one year has 12 months), so the equation will be:
3p=p(1+(.0557/365))^365t. Where, p is the beginning amound at t is the time it takes. You're right, just solve for t. If you need help with that, just ask! :)
EDIT:
Alrighty. So, you divide by p, to get 3=(1+(.0057/365))^365t. Now, we evaluate the inside to get 1.000015616, rounded to 9 decimal places. We now need to use logarithms to figure out what that t is. Trust me on this, or look up the mathematics behind it. We need that 1.0000... as the base for our log, and we need to have the actual subject of the log be the 3. Now that we have log base 1.000015616 of 3, we divide that atrocity by 365. We now get t to be equal to 192.7459133, rounded to 7 decimal places. While this does seem ungodly long, remember that everything in our problem is done in days. So, in reality, that just over half of a year.
Commutative property of addition is given by : a+b = b+a , where a and b can be any expression of real numbers. It basically changes the order of the so that simplification of any expression becomes easier.
but it is with the stuff that you have on your computer or paper
