X= a number
(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10
Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
8+12= 20
20=20
Hope this helps! :)
50.............................your welcome ;)
No. 4 squared is 16 and 16 + 79 is 85 not 88
Independent. The second event is not affected by the first event. Such as, if you pick up a card without replacement.
G(x) = 3x
g(x) = 3*( x )
g(f(x)) = 3*( f(x) ) ... every x has been replaced with f(x)
g(f(x)) = 3*( 3x ) ... replace the f(x) on the right side with 3x
g(f(x)) = (3*3)x
g(f(x)) = 9x