Given:
x, y and z are integers.
To prove:
If 
is even, then at least one of x, y or z is even.
Solution:
We know that,
Product of two odd integers is always odd. ...(i)
Difference of two odd integers is always even. ...(ii)
Sum of an even integer and an odd integer is odd. ...(iii)
Let as assume x, y and z all are odd, then is even.
is always odd. [Using (i)]
is always odd. [Using (i)]
is always even. [Using (ii)]
is always odd. [Using (iii)]
is always odd.
So, out assumption is incorrect.
Thus, at least one of x, y or z is even.
Hence proved.
Hello there!
Explanation:
↓↓↓↓↓↓↓↓↓↓↓↓↓
I gave you a hint.
You had to used PEMDAS.
P-Parenthesis
E-Exponents
M-Multiply
D-Divide
A-Add
S-Subtract
First you had to calculate with parenthesis first.
Then you calculate with exponents.
You had to multiply and divide you had go to left to right.
Then you add or subtract you had go to left to right.
Answer⇒⇒⇒⇒⇒⇒=-26
Hope this helps!
Thank you for posting your question at here on Brainly.
Have a great day!
-Charlie
Answer:
Step-by-step explanation:
Apply the law of exponents.
It is written/spoken like so:
"Twelve million three hundred and twenty four thousand nine hundred and four"
Answer:
d if "in2" means /2
Step-by-step explanation:
3x-4<u>=</u><u>9</u><u>0</u><u>-</u><u>3</u><u>4</u>
