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wlad13 [49]
3 years ago
14

If x = 10, find the value of:

%7D%20" id="TexFormula1" title=" \frac{2 {x}^{2}(x - 5) }{10x} " alt=" \frac{2 {x}^{2}(x - 5) }{10x} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
densk [106]3 years ago
7 0

Answer:

<h2><em>1</em><em>0</em></h2>

<em>solution \\  \frac{ {2x}^{2}(x - 5) }{10x}  \\  =  \frac{2  \times  {10}^{2}( 10 - 5)  }{10 \times 10}  \\  =  \frac{2 \times 100  \times 5}{100}  \\  =  \frac{1000}{100}  \\  = 10</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

vesna_86 [32]3 years ago
4 0

Answer:

10

Step-by-step explanation:

\frac{2(10)^2(10-5)}{10(10)}

Square the 10.

\frac{2(100)(10-5)}{10(10)}

Subtract 10 with 5.

\frac{2(100)(5)}{10(10)}

Multiply the numbers in the numerator.

\frac{2(500)}{100}

\frac{1000}{100}

Divide 1000 with 100.

=10

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Using relations in a right triangle, it is found that:

  • \sin{x} = \frac{6}{10} = 0.6
  • \cos{y} = \frac{6}{10} = 0.6
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<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
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The hypotenuse in this problem is given as follows:

h^2 = 6^2 + 8^2

h = \sqrt{100}

h = 10.

The sine of x is:

\sin{x} = \frac{6}{10} = 0.6

The cosine of y is:

\cos{y} = \frac{6}{10} = 0.6

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

More can be learned about relations in a right triangle at brainly.com/question/26396675

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