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2 years ago

14

Find the median,mode, and range for each set of number

2 answers:

4vir4ik [10]2 years ago

7 0

5, 5, 9, 12, 18, 22, 25 put numbers in order least to greatest
25 -5 = 20 that is the range
12 is the middle number this is the median
5 is the mode, it is the number that is repeated the most

NeTakaya2 years ago

6 0

Median is "middle". Put the numbers in order and find the middle number:
5, 5, 9, (12), 18, 22, 25
The median is 12.

mode is "most". Which number appears the most in the data set:
(5), (5), 9, 12, 18, 22, 25
The mode is 5.

mean is the "average". Find the sum and divide by the quantity.
5 + 5 + 9 + 12 + 18 + 22 + 25 = 96 & there are 7 numbers in the data set:
96/7 = 13.7
The mean is 13.7

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2 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

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Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

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Above equation can be written as 5 to the power of negative 5 over 6.

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