Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  
So you want:
−2kpk2q=0  
and
kpkq=−1  
and
2kpd2p−3kpdq+7=0  
Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .
Answer: there are no such linear functions.
 
        
             
        
        
        
Answer:
l:9
p:16.4
Step-by-step explanation:
l x w = A
A÷w=l
37.8÷4.4=9
2l+2w=P
18+8.4=16.4
 
        
             
        
        
        
<u>Answer:</u>
The correct answer option is 43%.
<u>Step-by-step explanation:</u>
We are given that 70% of students have blue eyes, 45% have dark hair, and 30% have blue eyes and dark hair. 
We are to find the probability of a student getting selected will have dark hair with blue eyes.
P(D|B) = P(D∩B) / P(B)
Substituting the given values in it to get:
P(D|B) = 0.3 / 0.7 = 0.428
Rounding it to the nearest whole percent we get:
0.428 × 100 = 42.8% ≈ 43%
 
        
             
        
        
        
Answer:
C. Add the equations
Step-by-step explanation:
 Adding both the equations will help eliminating 5y.
 
        
             
        
        
        
Answer:
- 1/6
Step-by-step explanation: