All categories

2 years ago

Please help!

Mathematics

1 answer:

lisabon 2012 [21]2 years ago

8 0

The leftmost line segment has a domain of -4 ≤ x < -1, or [-4, 1).

The central line segment has a domain of -1 ≤ x ≤ 2, or [-1, 2].

The rightmost line segment has a domain of 2 < x ≤ 5, or (2, 5].

Overall, this function has a domain of

[-4, 1) U [-1, 2] U (2, 5]

(where U means "union" in the set-theoretic notion)

But this also simplifies to the interval [-4, 5].

These correspond to the first and last choices.

You might be interested in

The points A, B, and C lie on a line so that AB = 12 cm and BC = 13.5 cm. Find the length of segment AC. Give all possible answe

natita [175]

Answer:

25.5 and 1.5

Step-by-step explanation:

AC = 12 cm

BC = 13.5 cm

12 + 13.5 = 25.5 cm

13.5 - 12 = 1.5 cm

4 0

3 years ago

Please help im doing a test and it’s due soon

swat32

Answer:

the answer is D.

Step-by-step explanation:

.............

7 0

3 years ago

Solve the variable in the following proportion. 3.6/y=1.2/2

Molodets [167]

Hello :
3.6/y=1.2/2
1.2 y = 2(3.6)
y = 2(3.6)/1.2
y=6

7 0

3 years ago

Combine the following fractions. a. 3/5 + 4/15 b. 5/6 - 1/4

Ne4ueva [31]

Hello there! :)

Answer:

1. $\boxed{\frac{13}{15} }$

2. $\boxed{\frac{7}{12} }$

Step-by-step explanation:

1. 3/5+4/15

First, you multiply by numerator and denominator.

3*3=9

5*3=15

$=\frac{9}{15}$

Then, you had to combine by the fractions.

$\frac{9}{15}+\frac{4}{15}$

Add by the numbers from left to right.

9+4=13

13/15 is the final answer.

______________________________________________

2. 5/6-1/4

First, you multiply by 2 both sides of numerator and denominator.

5*2=10

6*2=12

10/12

3/12

$\frac{10}{12}-\frac{3}{12}$

Subtract by the numerator.

10-3=7

7/12 is the final answer.

______________________________

Hope this helps!

Thanks!

Have a nice day! :)

-Charlie

7 0

3 years ago

Pleaseeee helpppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!

Semenov [28]

Answer:

KL = 50

Step-by-step explanation:

∆JML is similar to ∆JNL. it follows that:

[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]

JM = 4 + 20 = 24

JN = 4

JL = 10 + KL

JK = 10

Plug in the values

[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]

[tex] 6 = \frac{10 + KL}{10} [\tex]

Multiply both sides by 10

[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]

[tex] 60 = 10 + KL [\tex]

Subtract 10 from each side

[tex] 60 - 10 = KL [\tex]

[tex] 50 = KL [\tex]

KL = 50

6 0

3 years ago