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Alex787 [66]
3 years ago
5

I have a triangle with the angle measurements of 90 30 and 60° the side lengths are 5cm 7 cm and 5 cm what kind of triangle is i

t.
a right scalene triangle
a right isosceles triangle
an obtuse equilateral triangle
an acute scalene triangle ​
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

a right iscosceles triangle

Step-by-step explanation:

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Find the value of each variable using sine and cosine. Round your answers to the nearest tenth.
Alisiya [41]

Answer:

x ≈ 9.5 , y ≈ 15.3

Step-by-step explanation:

sin32° = \frac{opposite}{hypotenuse} = \frac{x}{18} ( multiply both sides by 18 )

18 × sin32° = x , then

x ≈ 9.5 ( to the nearest tenth )

cos32° = \frac{adjacent}{hypotenuse} = \frac{y}{18} ( multiply both sides by 18 )

18 × cos32° = y , then

y ≈ 15.3 ( to the nearest tenth )

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A sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8. If the sample mean corre
jeka57 [31]

Answer:

The value of the sample mean is 78.

Step-by-step explanation:

We are given that a sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8.

Also, the sample mean corresponds to a z score of 2.00.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for a sample mean is given by;

              Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = 70

            \sigma = standard deviation = 8

            n = sample size = 4

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, we are given that the sample mean corresponds to a z score of 2.00 for which we have to find the value of sample mean;</u>

So, <em><u>z-score</u></em> formula is given by ;

                  z-score = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } = \frac{\bar X-70}{\frac{8}{\sqrt{4} } }

                      2.00 =  \frac{\bar X-70}{\frac{8}{\sqrt{4} } }

                      2.00 =  \frac{\bar X-70}{4 } }

                     \bar X = 70+(2 \times 4)

                     \bar X = 70 + 8 = 78

<em>Therefore, the value of the sample mean is 78.</em>

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