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krok68 [10]
3 years ago
12

Helppppppppppppppppppppp

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0

Answer:c is -3

D is a and b

Step-by-step explanation:

UkoKoshka [18]3 years ago
3 0

Answer:

A. pretty straight forward- just put the numbers on the line

B. 0

C. Juniper Trail (E) because it has the closest elevation to 0

D. Little Butte (A) and Cradle Creek (B)- A is above sea level, B is below

E. Dinosaur Valley (C) because it has the lowest elevation there

Step-by-step explanation:

You might be interested in
-w/6 + 9 = 2 <br><br> PLZ ANSWER TODAY AND FAST I NEED IT RIGHT NOW
ahrayia [7]

Answer:

w = 42

Step-by-step explanation:

-w/6 + 9 = 2

subtract 9 from both sides

-w/6 + 9 - 9 = 2 - 9

-w/6 = 2 - 9

-w/6 = -7

multiply both sides by -6

-w/6 * -6 = -7 * -6

w = -7 * -6

w = 42

8 0
2 years ago
Justin wants to rent a boat and spend at most 36. The boat costs 6 per hour, and Justin has a discount coupon for 4 off. What ar
Maru [420]

Answer:

The possible numbers of hours Justin could rent the boat (0, 40/6]

Step-by-step explanation:

Let t represents the number of hours the boat is used,

∵ The boat costs 6 per hour,

So, the original cost of boat = 6t

Now, after getting $ 4 off

Final cost = 6t - 4

Now, final cost ≤ $ 36

\implies 6t - 4 \leq 36

6t\leq 36 + 4

6t \leq 40

t\leq \frac{40}{6}

Also, number of hours can not be negative

⇒ t ≥ 0

But, he must use the boat ⇒ t ≠ 0

Hence, the possible numbers of hours Justin could rent the boat,

(0, \frac{40}{6}]

7 0
3 years ago
For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
Read 2 more answers
ANSWER PLZ NOW HELPPPPP
jekas [21]

0.821 ≤ (-6.7+p)/(8.4) ⇒

0.821*8.4 ≤-6.7+p ⇒

6.8964≤-6.7+p ⇒

6.8964+6.7 ≤ p ⇒

13.5964 ≤ p

This is option C.

5 0
3 years ago
an airplaine descends 1.5 miles to an elevation of 5.25 miles. find the elevation of the plane before its descent
Maksim231197 [3]

We can then write an equation representing this problem as:

e−1.5mi=5.25mi

Now, add 1.5mi to each side of the equation to solve for e while keeping the equation balanced:

e−1.5mi+1.5mi=5.25mi+1.5mi

e−0=6.75mi

e=6.75mi

The plane's starting elevation was 6.75 miles

Hope this helps!

8 0
3 years ago
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