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3 years ago

Helppppppppppppppppppppp

Mathematics

2 answers:

alukav5142 [94]3 years ago

5 0

Answer:c is -3

D is a and b

Step-by-step explanation:

UkoKoshka [18]3 years ago

3 0

Answer:

A. pretty straight forward- just put the numbers on the line

B. 0

C. Juniper Trail (E) because it has the closest elevation to 0

D. Little Butte (A) and Cradle Creek (B)- A is above sea level, B is below

E. Dinosaur Valley (C) because it has the lowest elevation there

Step-by-step explanation:

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What is the first numbers of pi?

kirza4 [7]

3,141......
_____________________________

5 0

3 years ago

Read 2 more answers

Evaluate the expression.<br> 38 +16 - 12 - 2 - (302)<br> Enter your answer in the box.

masha68 [24]

Answer:

-262

Step-by-step explanation:

Evaluate Subtraction & Addition from right to left [or left to right, as long as you know what you are doing]:

38 + 16 - 12 - 2 - 302

|_______||____________|

$44 - 316 = -262$

I am joyous to assist you anytime.

5 0

3 years ago

7(2x-5)-11=3(5x-2)-2x

ICE Princess25 [194]

Answer:

x=40

Step-by-step explanation:

7(2x-5)-11=3(5x-2)-2x Distribute

14x-35-11=15x-6-2x Simplify

14x-46=13x-6 subtract 13x and add 46

x=40

5 0

3 years ago

Evaluate g (x) = 4- 3x when x = -3, 0, and 5

Nataliya [291]

Answer:

13, 4, -11

Step-by-step explanation:

g(-3) = 4-3(-3) = 4+9 = 13

g(0) = 4-3(0) =4-0 = 4

g(5) = 4-3(5) = 4-15 = -11

7 0

3 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

1 year ago