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BlackZzzverrR [31]
3 years ago
14

−6x+2x−5+2: simplified

Mathematics
1 answer:
Anestetic [448]3 years ago
3 0

Answer:

-4x-3

Step-by-step explanation:

all you do is combine like terms: -6x+2x=-4x and -5+2=-3

so the answer would be -4x-3

You might be interested in
A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
Question and answer in picture
Andrews [41]

Answer:

i think the answer is B but don't take my word for it


5 0
3 years ago
Read 2 more answers
Please help me !! pls pls pls
frutty [35]

Answer:

aas congruence postulate

6 0
2 years ago
the zeros of a parabola are -4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value o
natka813 [3]
Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant.  This is, the equation has the form:

y = a(x + 4)(x - 2)

Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:

10 = a (6 + 4) (6 - 2)

Therefore, any of these equivalent equations can be solved to determine the value of a:

10 = a 6 + 40) (6 -2)

10 = a (10)(4)

10 = 40a
7 0
3 years ago
Read 2 more answers
Help! Each week, Christian earns $x fixing bicycles and receives $10 as his allowance.
Zolol [24]
The answer is b: 2x+10
7 0
3 years ago
Read 2 more answers
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