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Vlad [161]
3 years ago
7

How to make a decimal a mixed number​

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:Step 1: Write down the decimal divided by 1, like this: decimal1

Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

Step 3: Simplify (or reduce) the fraction

Example: Convert 0.75 to a fraction

Step 1: Write down 0.75 divided by 1:

0.751

Step 2: Multiply both top and bottom by 100 (because there are 2 digits after the decimal point so that is 10×10=100):

× 100

right over arrow

0.751 = 75100

right under arrow

× 100

(Do you see how it turns the top number

into a whole number?)

Step 3: Simplify the fraction (this took me two steps):

÷5 ÷ 5

right over arrow right over arrow

75100 = 1520 = 34

right under arrow right under arrow

÷5 ÷ 5

Answer = 34

Step-by-step explanation:

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Answer: The answer is B

Step-by-step explanation:

The smaller the coefficient, the wider the graph would be. So the smallest number, if positive, 1/5 is the widest and the largest 7 is the narrowest.

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What is the surface area of a cube with a side of length 16 meters?
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Because it is a cube, you know all sides are equal and that there are 6 sides, so if you work out the area of one face, you can multiply it by 6. 16 × 16 = 256, which is one side, so therefore 256 × 6 = 1536 which is all 6 sides. I hope this helps!
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50/100 in tenth fraction and decimal form
Flura [38]

Answer:

5/10 and .5

Step-by-step explanation:

50/100 is 1/2 so 1/2 is equal to 5/10

5/10 is also 1/2 and 1/2 as a decimal is .5 or 0.5

hope it helps !

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3 years ago
Two sisters, sister A and sister B, play SCRABBLE with each other every evening. Sister A is a statistician, and she draws a ran
snow_tiger [21]

Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

Lower bound:

0.36 of 1450. So

0.36*1450 = 522

Upper bound:

0.69 of 1450. So

0.69*1450 = 1000.5

LCL = 522, UCL = 1000.5

Second question:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The project manager believes that p will turn out to be approximately 0.11.

This means that \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}

\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2

n = 417.9

Rounding up

A sample size no smaller than 418 is needed.

6 0
3 years ago
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