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3 years ago

What is the lateral area of a rectangular prism with a base length of 16 m, a base width of 8 m, and a height of 4 m?

Mathematics

2 answers:

dimaraw [331]3 years ago

8 0

Answer: B. $192\ m^2$

Step-by-step explanation:

The lateral area of a rectangular prism is given by :-

$\text{Lateral Area}=2h(l+w)$ , where h is the height, l is the length and w is the width of the rectangular prism.

Now, using the given information, the lateral area of the rectangular prism will be :-

$\text{Lateral Area}=2(4)(16+8)=8(24)=192\ m^2$

creativ13 [48]3 years ago

7 0

B. because you do 16*2*h + 8*2*h and you get 128 + 64 = 192

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podryga [215]

Answer:

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3 years ago

To buy a car, you borrow $25,000 with a term of three years at an APR of 6.5%. What is your monthly

Finger [1]

Answer:

$766.23

Step-by-step explanation:

The amortization formula is appropriate for this. (Better, use a financial calculator or spreadsheet.)

A = P(r/12)/(1 -(1 +r/12)^-(12t))

where P is the amount borrowed (25,000), r is the annual rate (0.065), and t is the number of years (3).

Putting the given numbers into the formula, we have ...

A = $25,000(0.065/12)/(1 -(1 +0.065/12)^(-36))

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A = $25,000(0.00541667)/(0.1767322)

A = $766.23

The monthly payment is $766.23.

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<em>Comment on tools</em>

A graphing or scientific calculator is useful for these. Something like a TI-84, or any of the equivalents, will have financial calculations like this built in. There are also numerous apps available for phone or tablet that will do financial calculations.

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3 years ago

Use induction to prove that 2? ?? for any integer n>0 . Indicate type of induction used.

Hoochie [10]

Answer with explanation:

The given statement is which we have to prove by the principal of Mathematical Induction

$2^{n}>n$

1.→For, n=1

L H S =2

R H S=1

2>1

L H S> R H S

So,the Statement is true for , n=1.

2.⇒Let the statement is true for, n=k.

$2^{k}>k$

---------------------------------------(1)

3⇒Now, we will prove that the mathematical statement is true for, n=k+1.

$\rightarrow 2^{k+1}>k+1\\\\L H S=\rightarrow 2^{k+1}=2^{k}\times 2\\\\\text{Using 1}\\\\2^{k}>k\\\\\text{Multiplying both sides by 2}\\\\2^{k+1}>2k\\\\As, 2 k=k+k,\text{Which will be always greater than }k+1.\\\\\rightarrow 2 k>k+1\\\\\rightarrow2^{k+1}>k+1$