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elixir [45]
2 years ago
8

5. Find mTOS in the figure below.

Mathematics
1 answer:
notka56 [123]2 years ago
4 0

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day!

We can solve this problem in a single step, that is using theory and a bit of algebra/elementary math.

We can start off by looking at the problem. We see that angles UOT and angle TOS both add up to 180 degrees

Since we know this, we can form the equation

Therefore, we know that <TOS is 52 degrees.

We can test this by adding up 52 and 128 and we should get 180.

128+52=180?\\180=180

Therefore, degrees.

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For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
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Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

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Step-by-step explanation:

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