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3 years ago

5. Find mTOS in the figure below.

Mathematics

1 answer:

notka56 [123]3 years ago

4 0

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day!

We can solve this problem in a single step, that is using theory and a bit of algebra/elementary math.

We can start off by looking at the problem. We see that angles UOT and angle TOS both add up to 180 degrees

Since we know this, we can form the equation

Therefore, we know that <TOS is 52 degrees.

We can test this by adding up 52 and 128 and we should get 180.

$128+52=180?\\180=180$

Therefore, degrees.

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A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day

-BARSIC- [3]

Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

$A(t) = A(0)e^{-kt}$

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

$A(t) = A(0)e^{-0.1392t}$

Find the substance's half life, in days.

This is t for which $A(t) = 0.5A(0)$ . So

$A(t) = A(0)e^{-0.1392t}$

$0.5A(0) = A(0)e^{-0.1392t}$

$e^{-0.1392t} = 0.5$

$\ln{e^{-0.1392t}} = \ln{0.5}$

$-0.1392t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.1392}$

$t = 4.98$

The substance half-life is of 4.98 days.

5 0

3 years ago

If m1=2x° and m3=3x° what is m1

olga_2 [115]

Answer:

Step-by-step explanation:

Using the angle addition postulate

angle 1+angle 2+angle 3=180

Angle 2 is 90 degrees,

Angle 1 is 2x degrees

Angle 3 is 3x degrees

Plug this into equation

$2x + 90 + 3x = 180$

$5x + 90 = 180$

$5x = 90$

$x = 18$

Plug 18 into 2x

$2(18) = 36$

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3 years ago

A new television measures 24" by 18". what is the length of the diagonal of the television?

Scorpion4ik [409]

Answer:

d=sqrt(18^2+24^2)=30

Step-by-step explanation:

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3 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$