Turn the points (3, -1) (-3, 5) into slope-intercept form. I found the answer online, but I need help on how to get it. (The ans

wer is y= -x + 2 just for reference)

Mathematics

1 answer:

Anettt [7]3 years ago

3 0

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-1)}{-3-3}\implies \cfrac{5+1}{-3-3}\implies \cfrac{6}{-6}\implies -1 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=-1(x-3) \\\\\\ y+1=-x+3\implies y=-x+2$

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Given the functions a(x) = 4x2 − x + 2 and b(x) = x + 1, identify the oblique asymptote of the function a of x over the function

olga2289 [7]

$a(x)=4x^2-x+2 \\
b(x)=x+1 \\ \\
f(x)=\frac{a(x)}{b(x)}=\frac{4x^2-x+2}{x+1}$

You can find the oblique asymptote by dividing the polynomial in the numerator by the polynomial in the denominator. The asymptote is the result of the division, without the remainder.
Look at the picture.

The oblique asymptote is $y=4x-5$ .