=12-5=7
=21-12=9
when u look at they have a diffrence of 2 so the answer will have a diffrence of 2 =11
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
The answer to your question is 74/99:D
I think it is 3/4 correct me if I’m wrong
AB = CB
Because they are congruent
Therefore CB = 5.9
Given perimeter = 17
CB+BE+ED+DC = 17
5.9 + BE + 2.8 + 5.6 = 17
BE + 14.3 = 17
BE = 17 - 14.3
= 2.7
Hope I helped
If I did please give brainlest answer
Thanks
