Answer:
Factoring the term
we get ![\mathbf{3(x+5)(x-5)}](https://tex.z-dn.net/?f=%5Cmathbf%7B3%28x%2B5%29%28x-5%29%7D)
Step-by-step explanation:
We need to solve the polynomial: ![3x^2-75](https://tex.z-dn.net/?f=3x%5E2-75)
First we see that 3 is common term, so taking 3 as common
![3(x^2-25)](https://tex.z-dn.net/?f=3%28x%5E2-25%29)
We know that 25 = 5x5 = 5²
So, replacing 25 with 5²
![3(x^2-5^2)](https://tex.z-dn.net/?f=3%28x%5E2-5%5E2%29)
We know that, ![a^2-b^2=(a-b)(a+b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29)
Applying this in our equation: ![x^2-5^2=(x+5)(x-5)](https://tex.z-dn.net/?f=x%5E2-5%5E2%3D%28x%2B5%29%28x-5%29)
![3(x+5)(x-5)](https://tex.z-dn.net/?f=3%28x%2B5%29%28x-5%29)
So, factoring the term
we get ![\mathbf{3(x+5)(x-5)}](https://tex.z-dn.net/?f=%5Cmathbf%7B3%28x%2B5%29%28x-5%29%7D)
Because M is the midpoint of AB, then AM and MB are equal distances. And because a segment can be written as the sum of its pieces, AM + MB = AB.
So,
AM + MB = AB <--- distance of a segment is the sum of its pieces
AM + AM = AB <--- M is the midpoint, so AM = MB
3x + 3 + 3x + 3 = 8x - 6 <--- substituting known amounts that were given
6x + 6 = 8x - 6 <--- collect like terms on the left side
6x = 8x - 12 <--- subtract 6 on both sides
-2x = -12 <--- subtract 8x on both sides
x = 6 <--- divide both sides by -2
Because x = 6, we put it back into AM. 3(6) + 3 = 18 + 3 = 21
Thus, AM is 21 units.
Answer in attachments below.
Hope This Helps
160 out of 400 equals : 160/400
If you shorten this, then you will get 2/5, which is the same as 40/100
Which will give you 40%
I hope this help you out