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Vikentia [17]
3 years ago
14

What is the GCF of the terms 14c²d and 42c³d? A. 2c²dB. 7c²dC. 3cD. 14c²d

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
GCF - What is the highest number possible that the two given terms have in common.

In the given problem, one can clearly see that the two share c^{2} and d.

The factors of 14 are 1, 2, 7 and 14 while the factors of 42 are 1, 2, 3, 6, 7, 14, 21 and 42.
Out of the two, 14 is the highest number that they both share.

So our answer will be 14c^{2} d
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This models exponential decay.
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Circle A has a diameter of 9 inches, a circumference of 28.26 inches, and an area of 63.585 square inches. The diameter of circl
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Please note that pi has just one value.  The only difference stems from round-off error when you don't use all of the digits following "3.14159 ... " to represent the value of pi.  The formula for circumference is C = 2 pi r, or C = pi d, 
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Circle A:  Diameter 9 inches and Circumference of 28.26 inches

If the diameter is 9 inches, then C = 28.26 inches = pi (9 inches).  Divide 28.26 inches by 9 inches.  Note that you MUST round off the ratio (pi) that you obtain, since 28.26 has 4 significant figures and 9 has just one.

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6 0
3 years ago
The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the
lana66690 [7]

Answer:

Width= 13 cm

length=30cm

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

Perimeter= 86 cm

According to the statement:

        Length= 2*Width+4\\L=2W+4

Perimeter of a rectangle= 2(Length+Width)

86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm

                               Width= 13 cm

                                length=30cm

6 0
3 years ago
The Anderson's are driving 2,563 miles to the beach. They plan to drive 325 miles a day. How many days will it take the Anderson
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Answer:

Around 8 days

Step-by-step explanation:

Divide 325 from 2,563

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Round that number

3 0
3 years ago
X+y+z=1<br> X-2y+3z=2<br> X+z-5=0
serious [3.7K]

x+y+z=1

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1-2y²-2yz+3yz+3z²=2(y+z)

(1-2y²+yz+3z²)/2=y+z

z=(1-2y²+yz+3z²)/2 -y/1

z=(1-2y²+yz+3z²-2y)/2

8 0
3 years ago
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