-20y+6(4y-10) Module 1 study guide

3A(48+C)<br> What is the answer

Roman55 [17]

Answer:

144A+3AC

Step-by-step explanation:

I think you provided half of the problem. Because this does not make sense to any problem I can think of.

3 0

3 years ago

How do you write 3,029,251 in word form

Dmitrij [34]

Three million twenty nine and two hundred fifty one

6 0

3 years ago

Read 2 more answers

The side length of a square garden is 15 feet. Find the area of the garden in square feet.

viktelen [127]

To find the area multiply the length by the width.

The length and width of a square are the same.

Area = 15 x 15 = 225 square feet.

8 0

2 years ago

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How do you do this question?

katovenus [111]

<h3>4 Answers: A, C, E, and F</h3>

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Explanation:

Choice A is true assuming we have $a_n = (-1)^n*b_n$

In this case, $a_n = (-1)^n*\frac{1}{\sqrt{n}}$ and $b_n = \frac{1}{\sqrt{n}}$

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Choice B is false. See choice A above.

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Choice C is true. The sequence $\{b_n\}$ is decreasing. As n gets larger, $b_n$ gets smaller. This is because the denominator is growing larger with the numerator held constant.

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Choice D is false. This contradicts choice C.

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Choice E is true since the denominator is growing forever

This is similar to $\displaystyle \lim_{n \to \infty} \frac{1}{n} = 0$

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Choice F is true due to choices C and E being true.

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Choice G is false because it contradicts choice F.

8 0

3 years ago

A random sample of 16 students selected from the student body of a large university had an average age of 25 years. We want to d

kenny6666 [7]

Answer:

$z=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

$p_v =2*P(Z>2)=0.0455$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean differs from 24 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=25$ represent the sample mean

$\sigma=2$ represent the sample population deviation for the sample

$n=16$ sample size

$\mu_o =24$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 24, the system of hypothesis would be:

Null hypothesis: $\mu = 24$

Alternative hypothesis: $\mu \neq 24$

If we analyze the size for the sample is < 30 but we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(Z>2)=0.0455$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean differs from 24 at 5% of significance

6 0

3 years ago