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3 years ago

10

I WILL AWARD BRAINLIEST!! PLEASE HELP!! Given: ΔABC, AB = AC X ∈ AC , Y ∈AB AX = AY Prove: BX = CY m∠ABC = m∠ACB △ABX≅△____, by

reason_____

1 answer:

EleoNora [17]3 years ago

6 0

Answer:

△ABX ≅ △ACY, by reason that they are equal and congruent to each other.

I hope this answers your question.

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6. A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to

Damm [24]

Find below attachment

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3 years ago

Increase 400 in the ratio 3:5

lesya [120]

Answer:

250.

Step-by-step explanation:

3 + 5 = 8. => (3/8) * 400 = 3 * 50 = 150. => (5/8) * 400 = 5 * 50 = 250.

4 0

3 years ago

Gustavo's bicycle cost $171.18 after a sales tax of 8%. write and solve an equation to find the price of the bike before the sal

Kryger [21]

Let x = price of the bike before a sales tax.

The price after a sales tax of 8% is
x + 0.08x = 1.08x dollars

Because the price paid was $171.18, therefore
1.08x = 171.18
x = 171.18/1.08 = $158.50

Answer: 158.50

3 0

4 years ago

A manager randomly selected 25 large cash transactions at a bank that were made in January. The manager then carefully tracked d

Dmitriy789 [7]

Answer:

0.4629 = 46.29% probability that the manager finds more than two such transactions

Step-by-step explanation:

For each transaction, there are only two possible outcomes. Either there is a procedural error, or there is not. The probability of a procedural error on a transaction is independent of any other transaction. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A manager randomly selected 25 large cash transactions at a bank that were made in January.

This means that $n = 25$

The chance for a procedural error is 10%

This means that $p = 0.1$

What is the probability that the manager finds more than two such transactions?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718$

$P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994$

$P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659$

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0718 + 0.1994 + 0.2659 = 0.5371$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5371 = 0.4629$

0.4629 = 46.29% probability that the manager finds more than two such transactions

4 0

3 years ago

Classify the quadrilateral. Then find the value(s) of the variable(s).<br><br> PLEASE HELP

bazaltina [42]

Answer:

A

Step-by-step explanation:

plug in y and x, if you want to be sure of each answer

In the case of A) here are the 2 equations, y-2=x+4 and 3x+4=x+6

now plug in what a describes

x=1, y=7

7-2=1+4 and 7=7

Therefore the answer is A

6 0

3 years ago