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tamaranim1 [39]
4 years ago
12

I’m not sure with this question help!

Mathematics
2 answers:
labwork [276]4 years ago
7 0

Answer:  C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

Step-by-step explanation:

3 to the power of negative 2 = 0.11111111111

3 squared is 1.73205080757

1.3 x 10 to the power of negative 1 = 0.13

1/3 converted to a decimal is 0.333

Now that we know what everything equals we know that anything that doesn't start with 3 squared is right and a little cheat is that only one of them start with 1/3 so we know that the second biggest is 1/3 so it is C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

oksian1 [2.3K]4 years ago
6 0
The answer is C he is correct
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1 hour, 32 min, HAHAHA not sure.
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A bacteria culture starts with 660 bacteria and grows at a rate proportional to its size. After 6 hours there will be 3960 bacte
scoray [572]

Answer:

a) P(t) = 660 e^{\frac{ln(6)}{6} t}

b) P(t=3) = 660 e^{\frac{ln(6)}{6}*3} = 1616.663 \approx 1617

Step-by-step explanation:

For this case we have the following info:

P(0) = 660 represent the initial amount of bacteria

P(6) = 3960 represent the population of bacteria after 6 hours

Part a

For this case we use the proportional model given by:

\frac{dP}{dt}= kP

Where P represent the population at time t and k is a constant of proportionality.

We can rewrite the model like this:

\frac{dP}{P} = k dt

And if we integrate both sides we got:

ln |P|= kt + C

Now if we apply exponential we got:

P = e^{kt +c}= e^{kt} e^C

P(t)= P_o e^{kt}

For this case using the initial condition:

660 = P_o e^{0k}, P_o = 660

We have the following model:

P(t) = 660 e^{kt}

Using the second condition P(6) = 3960 we have this:

3960 = 660e^{6k}

We can divide both sides by 660 and we got:

6= e^{6k}

Now we can apply natural log on both sides and we got:

ln (6)= 6k

k = \frac{ln(6)}{6}=0.2986265782

So then the model would be given by:

P(t) = 660 e^{\frac{ln(6)}{6} t}

Part b

For this case we just need to replace t=3 into the model and we got:

P(t=3) = 660 e^{\frac{ln(6)}{6}*3} = 1616.663 \approx 1617

4 0
3 years ago
Peter the optician sees 16 patients one Tuesday. 4 are neither short nor long sighted. The total number of short sighted patient
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Answer:

No of patients having longsightedness =  5

No of patient having shortsightedness = 7

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Step-by-step explanation:

Total no of patients = 16

As

No of patients  having neither long nor shortsightedness = 4

Let

No of patients having longsightedness = x

So

No of patient having shortsightedness = x+2

Equation becomes

x+(x+2)+4= 16\\2x+6 = 16\\2x= 16-6\\2x= 10\\x= \frac{10}{2} \\x= 5

Now

No of patients having longsightedness = x= 5

No of patient having shortsightedness = x+2      =5+2

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Answer:40 times

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given

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Total = Company A + Company B

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Total = 0.15*100% + 21%

Total = 15% + 21%

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3 years ago
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