All categories

3 years ago

Identify the slope and Y-Intercept from the equation: y=-2x+3 y=3x=3

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Answer:

y=-2+3 y-intercept = (0,3)

y=3x=3 = ???? there cant be 2 equal signs so i cant help with that question

Step-by-step explanation:

You might be interested in

Select all the expressions that are equivalent to - 2/5 (15-20d + 5c).

Nostrana [21]

One of them is -6+8d-2c

4 0

3 years ago

Please anyone I need help desperately

Montano1993 [528]

<h3>I think answer is </h3><h3>v = 176 cu ft</h3>

5 0

3 years ago

Read 2 more answers

1 7/9 as a mixed number

d1i1m1o1n [39]

Answer:

1 8/9

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Bill Baxter has 28,000 to invest for a year. You can lend it to a sister who has agreed to pay 8% simple interest for the year.

Firdavs [7]

Answer: Additional interest of $521.82 with a simple interest loan to sister generate.

Step-by-step explanation:

Since we have given that

Principal = $28000

Rate of interest at simple interest = 8%

Number of year = 1

so, Interest becomes,

$\dfrac{28000\times 8\times 1}{100}\\\\=280\times 8\\\\=\$2240$

Rate of interest compounded quarterly = 6%

Amount becomes,

$A=P(1+\dfrac{r}{400})^{4n}\\\\A=28000(1+\dfrac{6}{400})^4\\\\A=28000(\dfrac{406}{400})^4\\\\A=\$29718.18$

So, Interest would be

$Amount-Principal\\\\=29718.18-28000\\\\=\$1718.18$

Hence, Additional interest is given by

$2240-1718.18\\\\=\$521.82$

Hence, Additional interest of $521.82 with a simple interest loan to sister generate.

4 0

3 years ago

stat crunch A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least o

Masteriza [31]

Answer:

The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 250, \pi = \frac{41}{250} = 0.164$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.164 - 2.575\sqrt{\frac{0.164*0.836}{250}} = 0.104$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.164 + 2.575\sqrt{\frac{0.164*0.836}{250}} = 0.224$

The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).

5 0

3 years ago