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daser333 [38]
3 years ago
11

U need help ASP .f(x)=1-3X and g (x)=x+4 calculate gf(-2)​

Mathematics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

gf (-2) = 11

Step-by-step explanation:

f(x) = 1 - 3x \\ g(x) = x + 4 \\ gf( - 2) = ..

gf = .. \\ g(1 - 3x) \\  = 1 - 3x + 4 \\  =  - 3x + 5 \\ gf =  - 3x + 5

gf( - 2) =  - 3( - 2) + 5 \\  = 6 + 5 = 11

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Write a<br> as a repeating decimal.<br> Write 2/5 as a repeating decimal.
Svet_ta [14]

Answer:

0.4

Step-by-step explanation:

2/5 = 4/10

4/10 = 0.4

2/5 is not a repeating decimal.

Hope This Helps :)

6 0
3 years ago
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A fly-fishing line is cast in a parabolic motion with an initial velocity of 30 meters per second at an angle of 60° to the hori
drek231 [11]

Answer:

1. 40

2. 1.3

Step-by-step explanation:

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2 years ago
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Emmet has already baked 2 pies, and he can bake 2 pies with each additional cup of sugar he buys. How many additional cups of su
ANTONII [103]

Answer:

19

Step-by-step explanation:

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5 0
2 years ago
The state of mishgan recored an all time high snowball of 355.9 inches during the winter of 1978-79 its lowest snowfall of 81.3
Rama09 [41]

Answer:

<u>274.6 inches</u> more snowfall Michigan received during the winter of 1978-79 than in 1930-31.

Step-by-step explanation:

Given:

The state of Michigan recorded an all time high snowfall of 355.9 inches during the winter of 1978-79.

Its lowest snowfall of 81.3 inches was recorded during the winter of 1930-31.

Now, to find how much more snowfall did Michigan received during the winter of 1978-79 than in 1930-31.

The snowfall in 1978-79 = 355.9 inches.

And, the snowfall in 1930-31 = 81.3 inches.

So, to get the how much more snowfall in 1978-79 than 1930-31 we subtract:

Snowfall in 1978-79 - Snowfall in 1930-31.

355.9\ inches-81.3\ inches = 274.6\ inches.

Therefore, 274.6 inches more snowfall Michigan received during the winter of 1978-79 than in 1930-31.

8 0
3 years ago
I need answers asap... please
aleksandrvk [35]

Answer:

see explanation

Step-by-step explanation:

(4)

consider the left side

factor the numerator

cosx - cos³x = cosx(1 - cos²x)

\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}

cancel sinx on numerator/denominator

= cosxsinx =right side ⇒ verified

(5)

Consider the left side

expand the factors

(1 + cotΘ)² + (1 - cotΘ)²

= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ

= 2 + 2cot²Θ

= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ

= 2cosec²Θ = right side ⇒ verified

(6)

Consider the left side

the denominator simplifies to

cosxtanx = cosx × \frac{sinx}{cosx} = sinx

\frac{sin^2x(secx+cosecx)}{sinx}

= sinx( \frac{1}{cosx} + \frac{1}{sinx})

= \frac{sinx}{cosx} + \frac{sinx}{sinx}

= tanx + 1 = right side ⇒ verified











3 0
3 years ago
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