In triangle ABC, find B, to the nearest degree, given a = 7, b = 10, and C is a right angle.

Mathematics

2 answers:

padilas [110]3 years ago

5 0

Answer:

55°

Step-by-step explanation:

Since ΔABC is right we can use the tangent ratio to find ∠B

tanB = $\frac{opposite}{adjacent}$ = $\frac{10}{7}$ , hence

B = $tan^{-1}$ ( $\frac{10}{7}$ ) = 55°

Alexxandr [17]3 years ago

5 0

The correct answer is D 55.

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