Question

In triangle ABC, find B, to the nearest degree, given a = 7, b = 10, and C is a right angle.

Answer 1

Answer:

55°

Step-by-step explanation:

Since ΔABC is right we can use the tangent ratio to find ∠B

tanB = $\frac{opposite}{adjacent}$ = $\frac{10}{7}$, hence

B = $tan^{-1}$($\frac{10}{7}$) = 55°

Answer 2

The correct answer is D 55.