We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
If you want to learn more, you can read:
brainly.com/question/1349408
Answer: x > 486
Explanation:
We have some number x and we divide that by 18. The result is larger than 27. To find possible values for x, we need to undo what is happening to x. The opposite of division is multiplication. We multiply both sides by 18 to cancel out the "18" on the left side, which will isolate x to get it to its own side.
This is what the steps look like
x/18 > 27
18*( x/18 ) > 18*27 .... multiplying both sides by 18
x > 486 ... note the 18's cancel on the left side
So this means x is some number greater than 486.
Answer:
340 in.
Step-by-step explanation:
L x W x H
17 x 4 x 5 = 340
The answer to this problem is simple all you have to do is pemdas and you get the answer 0.6
The answer i thinkkk would be,
x < -1
