The process of preventing exceptions from causing runtime errors is called exception handling.
This type of handling deals with exceptions in particular, which are all anomalies that will prevent the computer from doing its usual job. So those exceptions will be handled even before they get the chance to cause errors which will disturb the operations that the computer is carrying out.
Answer:
Tony is a 45-year-old psychiatrist who has net earned income of $300,000 in 2020. What is the maximum amount he can contribute to his SEP for the year? 300,000x.25= 75,000 or $57,000
$57,000
Explanation:
Answer:
Betty Incorporated
Journal Entries:
June 3:
DR Inventory $7,100
CR Accounts Payable (North Inc.) $7,100
To record the purchase of goods on account with terms 2/10, n/30.
June 5:
DR Accounts Payable (North Inc.) $2,600
CR Inventory $2,600
To record the return of goods on account.
June 6:
DR Inventory $2,500
CR Accounts Payable (South Corp.) $2,500
To record the purchase of goods on account with terms 2/10, n/30.
June 11:
DR Accounts Payable (North Inc.) $4,500
CR Cash Account $4,410
CR Cash Discount $90
To record the payment of balance owed to North Inc.
June 22:
DR Accounts Payable (South Corp.) $2,500
CR Cash Account $2,500
To record the payment of balance owed to South Corp.
Explanation:
The trade terms 2/10, n/30 mean that both North Inc. and South Corp. offered 2% cash discounts on amount paid by Betty Incorporated if it could settle its bills within 10 days. The net allowed credit days are 30 days, after which Betty Incorporated could be charged interest for late payment. It did not utilize the discount offered by South Corp. as it paid its bills after 16 days instead of within 10 days as stated in the trade terms.
Answer:
$6,480,000
Explanation:
The computation of the amount of the current liabilities is shown below:
Total assets of $11,200,000
Less: Noncurrent assets $1,480,000
Current Assets = $9,720,000
Now as we know that
Current ratio = Current Assets ÷ Current Liabilities
Current Liabilites is
= $9,720,000 ÷ 1.5
= $6,480,000
hence, the current liabilities is $6,480,000
