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4 years ago

Simplify. (6x – 5 + 4x2) + (2x - 2)

Mathematics

2 answers:

myrzilka [38]4 years ago

6 0

First, I would eliminate the parenthesis:

6x - 5 + $4x^{2}$ + 2x - 2

Then, you can combine like terms:

6x + 2x - 5 - 2 + $4x^2$

8x - 7 + $4x^{2}$

This is your answer, but you can rearrange it so the degrees are in order:

$4x^2$ + 8x - 7

Pie4 years ago

3 0

(6x-5+4x2)+(2x-2)
6x+4x-3
10x-3
10x-3+2x-2
12x-3+-2
12x-5

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Can you please help me solve for the area

ycow [4]

Answer:

area is equal to 198 cm^2

Step-by-step explanation:

the height h of the left triangle can be obtained by

Pytagoras theorem:

$5^2+h^2=13^2\\25+h^2=169\\h^2=169-25\\h^2=144\\h=\sqrt{144} \\h=12$

the, the area of the left triangle is

$A_1=\frac{5*12}{2} \\A_1=5*6\\A_1=30$

the area of the right triangle is

$A_2=\frac{2*12}{2} \\A_2=12$

and the area of the rectangle in the middle is

$A_3=(13)(12)\\A_3=156$

Por tanto, el area total sera

$A=A_1+A_2+A_3\\A=30+12+156\\A=198$

8 0

3 years ago

Help me, please!!!!! CORRECT ANSWER GETS BRAINLIEST!!!!!!

katen-ka-za [31]

Hello,

Here is your answer:

The proper answer to your question is..... 200,000=4x-20

When your doing questions like these make sure you pay attention to the question.

Your answer is 200,000=4x-20

If you need anymore help feel free to ask me!

Hope this helps!

5 0

4 years ago

SOLVED

Nastasia [14]

5)
a. The equation that describes the forces which act in the x-direction:
 Fx = 200 * cos 30 

b. The equation which describes the forces which act in the y-direction: 
 Fy = 200 * sin 30 

c. The x and y components of the force of tension: 
 Tx = Fx = 200 * cos 30 
 Ty = Fy = 200 * sin 30 

d.Since desk does not budge, frictional force = Fx
= 200 * cos 30 

 Normal force = 50 * g - Fy
= 50 g - 200 * sin 30
____________________________________________________________
6) Let F_net = 0
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),

The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N

4 0

4 years ago

What is the equation of a vertical line passing through the point (3, 5)?

-BARSIC- [3]

D. x=3
I don't really know how to explain it other than the only points on the line are sitting at the x=3 and y=anything

7 0

3 years ago

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The five members of the Traynor family each buy train tickets. During the train ride, each family member buys a boxed lunch for

larisa [96]

Let's assume

the price of each train ticket is x