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Sonbull [250]
4 years ago
11

Assume that adults have it scores that are normally distributed with a mean of 100 standard deviation of 15 find probability tha

t randomly selected adult has an Iq between 89 and 111
Mathematics
1 answer:
exis [7]4 years ago
4 0

Answer:

0.5346

Step-by-step explanation:

Find the z-scores.

z = (x − μ) / σ

z₁ = (89 − 100) / 15

z₁ = -0.73

z₂ = (111 − 100) / 15

z₂ = 0.73

Find the probability.

P(-0.73 < Z < 0.73)

= P(Z < 0.73) − P(Z < -0.73)

= 0.7673 − 0.2327

= 0.5346

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PLEASE SOLVE IT WITH EXPLANATION!!<br>DONT TAKE POINTS :)<br>​
zloy xaker [14]

Step-by-step explanation:

We are asked to simply (2√5 + 3√2)². Using formula: (a + b)² = a² + b² + 2ab. Let's say 2√5 = a, 3√2 = b. So,

→ (a + b)² = a² + b² + 2ab

→ (2√5 + 3√2)² = (2√5)² + (3√2)² + 2(2√5)(3√2)

We are aware about the fact that root means 1/2 and square of root means 2/2 that is 1. Using this we get:

→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2√5)(3√2)

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→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2*3)(√5)(√2)

Solve the rest calculations.

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4 0
3 years ago
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Marrrta [24]

Answer:

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*I=5*

Step-by-step explanation:

I basically just found the scale factor/proportion from two given sides and then used that to find the remaining sides.

*I'm not sure about 'I' since the edge of the paper was cut off so I want sure if it was a 5 or a 15 on the left most problem in the third row. I assumed it was 15. If it's not, just shout it out in the comments and I'll fix it! :)*

You can fill the letters in at the bottom XD

I hope this helped! :D

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