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Rasek [7]
2 years ago
9

(20 pts) How would I graph a slope that passes through a certain point? Is there a certain equation that could help me? Say for

example I want to graph y=x/4 but have it pass through (-1, -1/3)
Mathematics
1 answer:
Ronch [10]2 years ago
4 0

Answer:

Use point-slope form.

Step-by-step explanation:

Let us say (x1, y1) are the coordinates you want to pass through and m is the slope, you would right it like this:

y-y1=m(x-x1)

In this case, the slope is 1/4 and it passes through (-1, -1/3)

y+1/3=1/4(x+1)

If you want to simplify this, you get

y=x-1/12

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this graph shows the amount of rain that falls in a given amount of time. what is the slope of the line and what does it mean in
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-5/-2 or 2.5

Step-by-step explanation:

Because you gave two points that I'm guessing are from the graph I think that's the answer. Because when you use the slope formula y2-y1 over x2 - x1 you get -5/-2 or you either get 2.5 meaning that is the slope specifically saying the rate of change. You get 2.5 when you divide -5/-2 incase you need a decimal or want to simplfy it.

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Name the relationship between the angles below. What is the sum of the angles? Explain how you would find the missing angle. Exp
DiKsa [7]

Answer:

would find the missing angle. Explain each step. (replace with 120 & x)

Name the relationship between the angles below. What is the sum of the angles? Explain how you would find the missing angle. Explain each step. (replace with 120 & x)

Step-by-step explanation:

Name the relationship between the angles below. What is the sum of the angles? Explain how you would find the missing angle. Explain each step. (replace with 120 & x)

8 0
2 years ago
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
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