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3 years ago

9

An acute angel measure is

2 answers:

anzhelika [568]3 years ago

4 0

An acute angle measure is always less than 90 degree

zepelin [54]3 years ago

3 0

Acute is less than 90 obtuse is more than 90 right is 90

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An image has a different orientation and size than the original figure. Which two transformations could have been applied to the

nalin [4]

I think it is A
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8 0

3 years ago

Given triangle DEF similar to triangle GHF. Enter segments in the blanks provided that would result in a true equation.

Paul [167]

Given:

The triangles DEF is similar to GHF.

The objective is to find a similar ratio of DF/DE.

Explanation:

Using the basic proportionality theorem, for the similar triangles DEF and GHF,

$\frac{DE}{GH}=\frac{DF}{GF}=\frac{EF}{HF}\text{ . . . . .. .(1)}$

Considering the first two ratios of equation (1),

$\frac{DE}{GH}=\frac{DF}{GF}$

On interchanging the segments further,

$\frac{DF}{DE}=\frac{GF}{GH}$

Hence, the required segment in the blanks is GF/GH.

4 0

2 years ago

Helpppppppppppppppppppp plsss

insens350 [35]

Answer:

25

Step-by-step explanation:

he got an 80 so if that was his grade by answering 20 questions right then the correct answer would be 25 questions

5 0

3 years ago

Let $M$ be the least common multiple of $1, 2, \ldots, 20$. How many positive divisors does $M$ have

Veronika [31]

Consider the prime factorization of 20!.

$20! = 20 \times 19 \times 18 \times \cdots \times 3 \times 2 \times 1$

The LCM of 1, 2, ..., 20 must contain all the primes less than 20 in its factorization, so

$M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times m$

where $m$ is some integer not divisible by any of these primes.

Compare the factorizations of the remaining divisors of 20!, and check off any whose factorizations are already contained in the product of primes above.

$4 = 2^2$ - missing a factor of 2

$6 = 2\times3$ - ✓

$8 = 2^3$ - missing a factor of 2²

$9 = 3^2$ - missing a factor of 3

$10 = 2\times5$ - ✓

$12 = 2^2\times3$ - missing a factor of 2

$14 = 2\times7$ - ✓

$15 = 3\times5$ - ✓

$16 = 2^4$ - missing a factor of 2³

$18 = 2\times3^2$ - missing a factor of 3

$20 = 2^2\times5$ - missing a factor of 2

From the divisors marked "missing", we add the necessary missing factors to the factorization of $M$ , so that

$M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times 2^3 \times 3$

Then the LCM of 1, 2, 3, …, 20 is

$M = 2^4 \times 3^2 \times 5 \times7 \times 11 \times 13 \times17 \times 19$

$\implies \boxed{M = 232,792,560}$

3 0

2 years ago

What is the angle of depression from the start of a 6-foot-high access ramp that ends at a point 40 feet away along the ground?

NISA [10]

Answer:

8.53°

Step-by-step explanation:

Observe the attached image.

The ramp forms an alpha angle triangle with an opposite side of 6 ft and an adjacent side of 40 ft.

We know that the tangent of an angle is defined as:

$tan(\alpha) = \frac{opposite\ side}{adjacent\ side}$

So:

$tan(\alpha) = \frac{6}{40}$

To clear the angle we apply the inverse of the tangent (arctangent) on both sides of the equation:

$atan(tan(\alpha)) =atan(\frac{6}{40})$

$\alpha= atan(\frac{6}{40})\\\\\alpha = 8.53\°$

5 0

3 years ago