9514 1404 393
Answer:
- time: 1.122 seconds
- range: 10.693 m
- maximum height: 1.543 m
Explanation:
<u>Given</u>:
runner is launched at 30° angle to horizontal at 11 m/s
acceleration due to gravity is g = -9.8 m/s²
<u>Find</u>:
runner's hang time
runner's distance to the landing point
runner's maximum height
<u>Solution</u>:
The (horizontal, vertical) speed components will be ...
(11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)
The time of flight can be found from the height formula:
h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch
The time we're concerned with is the time when h(t)=0 and t>0.
0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)
The second factor is zero when ...
t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time
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The distance to the landing point will be the product of horizontal speed and hang time:
d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing
__
The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...
h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height
Organ System, Organ coll, tissue
Answer:
C
Explanation:
The answer is C i think but i ould be wrong
Answer:
it is similar because it involves multiple body parts.
it is different because it doesn't involve breaking down anything or providing things through the blood.
hope i helped...............mark me brainliest?
Answer:
50%
Explanation:
According to the given information, the allele for the red-green colorblindness is inherited in an X linked recessive manner. Let's assume that the allele X^c is responsible for red-green colorblindness. The woman is normal but had a colorblind father (X^cY). Fathers give their X chromosomes to the daughters while their Y chromosome is transmitted to their sons. The sons get their X chromosomes from the mother.
The colorblind father has transmitted the X-linked allele for the red-green colorblindness to his daughter. Therefore, the genotype of the woman is X^cX. The woman would produce two types of eggs: 50 % with X^C and 50% with X. Therefore, 50% of sons of this woman would get X linked allele for the red-green colorblindness and would be affected by the disorder while the rest 50% of her sons will be normal.