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3 years ago

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The perimeter of a rectangular park is 208 m. Its length is 2m more than twice its breadth. What are the length and breadth of t

he park?

1 answer:

FromTheMoon [43]3 years ago

7 0

Answer:

x = length = 70m

y = breadth = 34m

Step-by-step explanation:

to check whether its right:

perimeter of park

= length + length + breadth + breadth

= x + x + y + y

= 70 + 70 + 34 + 34

= 140 + 68

= 208m

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Candice bought a pencil box, shown below, to take with her to school

Phoenix [80]

Answer:

50.75

Step-by-step explanation:

You Just have to multiply length - width - and height - and you're good to go!

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3 years ago

Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

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2 years ago

What is the value of x

mixer [17]

FOR Y
opposite angles - equal
angles in a quadrilateral are 360 degrees
68 + 68 = 136
360 - 136 = 224
224/2 = 112 degrees
angles on a straight line = 180 degrees
180 - 112 = 68
Y = 68
FOR X
angles on a straight line are 180 degrees
180 - 68 = 112 degrees
X=112 degrees

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3 years ago

balandron [24]

Answer: (2x + 3) • (x-1)

Step-by-step explanation:

1 Pull out like factors :

4x + 6 = 2 • (2x + 3)

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

(5x - 5) = 5 • (x - 1)

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3 years ago

Recall that in a 30 – 60 – 90 triangle, if the shortest leg measures x units, then the longer leg measures xStartRoot 3 EndRoot

Brums [2.3K]

The area of the shaded region is $\rm (150\sqrt{3} \ - 75\pi ) \ feet^2$ option first is correct.

It is given that a circle is inscribed in a regular hexagon with sides of 10 feet.

It is required to find the shaded area (missing data is attached shown in the picture).

<h3>What is a circle?</h3>

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have a hexagon with a side length of 10 feet.

We know the area of the hexagon is given by:

$\rm A = \frac{3\sqrt{3} }{2} a^2$ where a is the side length.

$\rm A = \frac{3\sqrt{3} }{2} 10^2$ ⇒ $150\sqrt{3}$ $\rm feet^2$

We have the shortest length = x feet and from the figure:

2x = 10

x = 5 feet

The radius of the circle r = longer leg

$\rm r = x\sqrt{3} \Rightarrow 5\sqrt{3}$ feet

The area of the circle a = $\pi r^2$ ⇒ $\pi (5\sqrt{3} )^2 \Rightarrow 75\pi \ \rm feet^2$

The area of the shaded region = A - a

$\rm =(150\sqrt{3} \ - 75\pi ) \ feet^2$

Thus, the area of the shaded region is $\rm (150\sqrt{3} \ - 75\pi ) \ feet^2$

Learn more about circle here:

brainly.com/question/11833983

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2 years ago