Question

Helppp it's due today​

Answer 1

let Q= 30°

Perpendicular (P) = X

Base ( B) = Y

Hypotenuse (H) = 10

$\sin(Q) = \frac{p}{h} \\ \\ now \: \: \: \: \: \: \: \: \: \: \\ \\ \\ sin30 = \frac{x}{10} \\ \\ \ \frac{1}{2} = \frac{x}{10} \\ \\ 2x = 10 \\ \\ x = \frac{10}{2} \\ \\ x = 5 \\ \\ cos30 = \frac{b}{h} \\ \\ \frac{ \sqrt{3} }{2} = \frac{y}{10} \\ \\ 2y = 2 \sqrt{3} \\ \\ y = \frac{2 \sqrt{3} }{2} \\ \\ y = \sqrt{3}$

Answer 2

Answer:

x = 5 and y = 8.7

See attached image for working

Step-by-step explanation:

Since it's a right angle triangle you can use sin and cos.