Find e-0.3 A) -0.74 B) 0.74 C) -1.35
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Answer:
The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
Step-by-step explanation:
Consider the provided information.
The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .
Thus, n = 12, σ = 5000
degrees of freedom = n-1 = 12-1 = 11
Formula to find the value of z is:
Where is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.
Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.