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alexira [117]
3 years ago
15

Question 6

Mathematics
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

m=Y2–Y1/X2–X1

m =    \frac{  - 9 - (6)}{1 - ( - 4)}  \\ m =  \frac{ - 15}{5}  =  - 3 \\ y = mx + b \\ y = - 3x + b

Vesnalui [34]3 years ago
3 0

Answer: y = -5x - 14

Step-by-step explanation:

first find the difference between the x variables x1 = 1 and x2=-4 to find the slope(m)

-4 - 1 = -5

next find the difference between the y variables to find b

-9 - 6 = -14

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Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
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If

\displaystyle g(x) = \int_0^x f(t) \, dt

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In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

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\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

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since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

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since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

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