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Mariulka [41]
4 years ago
12

In a study of pleas and prison​ sentences, it is found that 6060​% of the subjects studied were sent to prison. Among those sent

to​ prison, 4646​% choose to plead guilty. Among those not sent to​ prison, 3636​% choose to plead guilty. a. If one of the study subjects is randomly​ selected, find the probability of getting someone who was not sent to prison. b. If a study subject is randomly selected and it is then found that the subject entered a guilty​ plea, find the probability that this person was not sent to prison.
Mathematics
1 answer:
Dovator [93]4 years ago
7 0

Answer:

a. 40 %

b. 34.3 % ( approx )

Step-by-step explanation:

Let S is the event of the subjects studied that were sent to prison,

S' is the event of the subjects studied that won't sent to prison,

G is the event of pleading guilty,

G' is the event of not pleading guilty,

According to the question,

P(S) = 60% = 0.6 ⇒ P(S') = 1 - P(S) = 1 - 0.6 = 0.4,

P(S∩G) = 46% of 60% = 0.46 × 0.60 = 0.276,

P(S'∩G) = 36% of 40% = 0.36 × 0.40 = 0.144,

P(G) = P(S∩G) + P(S'∩G) = 0.276 + 0.144 = 0.42

a. The of getting someone who was not sent to prison, P(S') = 0.4,

b. the probability that this person was not sent to prison when it is given that the subject entered a guilty​ plea,

P(\frac{S'}{G})=\frac{P(S'\cap G)}{P(G)}=\frac{0.144}{0.42}\approx 0.343=34.3\%

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<h2>Thus, the required "option 4)"  is correct.</h2>

Step-by-step explanation:

We find,

(x+2y)^7

To find, the binomial expansion of of (x+2y)^7 = ?

We know that,

(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n

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Here, n = 7, x = x and y = 2y

(x+2y)^7= ^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

∴ The binomial expansion of of (x+2y)^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

Thus, the required "option 4)"  is correct.

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