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3 years ago

12

4/1=12/3,so 12 cups = quarts

2 answers:

REY [17]3 years ago

5 0

Yeah I think so I just took a wild guess and looked at my measurement sheet

m_a_m_a [10]3 years ago

5 0

The right answer is 12 cups = 3 quarts

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The bases of a trapezoid are 12 and 24. what is the length of the midsegment?

Mandarinka [93]

Answer:

18

Step-by-step explanation:

The midsegment is calculated as

$\frac{sumofbases}{2}$ = $\frac{12+24}{2}$ = $\frac{36}{2}$ = 18

8 0

3 years ago

Step by step to this please

vladimir1956 [14]

Answer:

7

Step-by-step explanation:

1) Substitute the values of t, v, and w into the expression:

$(-2)^{2} + (1)(3)$

2) Simplify the terms:

$(-2)^{2} + (1)(3)\\=4 + 3\\= 7$

6 0

3 years ago

Read 2 more answers

Dmitriy789 [7]

Answer:

The product of given two fractions is

$\frac{4(x+2)}{(x-1)(x+3)}$

Therefore $\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}$

Step-by-step explanation:

Given expression is

$\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}$

To find the product of two given fractions as below :

$\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{2(5)}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}$

$=\frac{10}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}$

$=\frac{20x(x+2)}{5x(x-1)(x+3)}$

$=\frac{20x^2+40x}{(5x^2-5x)(x+3)}$ (multiply each term in the factor to each term in the another factor )

$=\frac{20x^2+40x}{5x^3+15x^2-5x^2-15x}$ ( adding the like terms )

$=\frac{20x^2+40x}{5x^3+10x^2-15x}$

$=\frac{5x(4x+8)}{5x(x^2+2x-3)}$

$=\frac{4(x+2)}{(x-1)(x+3)}$

Therefore $\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}$

Therefore the product of given two fractions is $\frac{4(x+2)}{(x-1)(x+3)}$

6 0

3 years ago

The equation of this graph is

san4es73 [151]

Is this what you need or? Y= 1/4x +3

4 0

2 years ago

Read 2 more answers

Formula for the surface area of a cylinder, SA = 2ar2 + 2arh. Solve for h.

MakcuM [25]

Answer:

$h=\frac{SA-2\pi r^2}{2\pi r}$

Step-by-step explanation:

The formula for the surface area of a cylinder is:

$SA=2\pi r^2+2\pi rh$

And we want to solve for the height h.

First, subtract $2\pi r^2$ from both sides. This yields:

$2\pi rh=SA-2\pi r^2$

Now, divide both sides by $2\pi r$ . This yields:

$h=\frac{SA-2\pi r^2}{2\pi r}$

And we're done!

8 0

3 years ago