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mihalych1998 [28]
3 years ago
8

Evaluate the following expressions, and justify your answers. WhatPower7(49)

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

whatpower7(49) = 2

Step-by-step explanation:

given data  

WhatPower7(49)

to find out

Evaluate the expressions WhatPower7(49)

solution

as we know that whatpower mean exponent of equation so we get by given equation  

we know whatpower7(49) = 2

because  

we know that  7 × 7 = 49  

so that 7² = 49

so that  the exponent  is here 2 for 7 that become 49

so correct answer is 2

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A basketball player has 45 steals, 72 assists, 90 rebounds, and 432 points. What is
aalyn [17]

Answer:

5:24

Step-by-step explanation:

We're provided with the number of rebounds as 90 while the points are 432. Expressing them into ratio of rebounds to steals we have

90:432

Simplification:

Dividing both sides by 2 we obtain

45:216

Dividing both sides of the above ratio by 3 we obtain

15:72

Dividing both sides of the above ratio further by 3 we obtain

5:24

Therefore, rhe simplified ratio of rebounds ro steals is 5:24

8 0
3 years ago
Please help!! Thanks in advance :)
Alisiya [41]

Answer:

180 plants  

Step-by-step explanation:

the area of a right triangle is: ab/2

side a = 8

side b = 15

8 x 15 = 120

120/2 = 60

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7 0
3 years ago
Read 2 more answers
Can someone help me please
tamaranim1 [39]

all shapes with 4 angles are 360 degrees

100+96= 196

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80+84=164

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4 0
3 years ago
Read 2 more answers
If 2= (1+ r)^7 solve the equation for r?​
solong [7]

7 = r^1/2 is the same as saying 7 = square root of r. So, to get rid of the square root sign on the r, you need to square it, and when you do something to one side of the equation, you have to do the same to the other side. So after squaring both sides, you get 49 = r.

8 0
3 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively. Pl
kicyunya [14]
Hello,

u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \  r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \  a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\


8 0
3 years ago
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