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3 years ago

An expression of 40%

Mathematics

2 answers:

Sveta_85 [38]3 years ago

7 0

Answer:

40% = 40/100 = 0.4

Step-by-step explanation:

BabaBlast [244]3 years ago

7 0

Answer:

There's two answers.

Step-by-step explanation:

Anyways, so we have 40% as a dollar, which would be $0.40. We also have 40% as 0.4, which is really the same as the dollar example. We also could have 40% represented as being 40% off something at a store. Same the jacket you want is $110, but is being sold for 40% off. Just take 110 and multiply is by 0.4. Your answer is 44. The jacket is $44 less than normal making it only $66. Hope this helps!

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Use the graph to determine

gtnhenbr [62]

Answer:

a) Domain: x≥0

b) Range: y≤-2

c) x-intercepts: None

d) y-intercepts: (0,-2)

e) f(4)= -4

Step-by-step explanation:

If this helps please mark as brainliest

5 0

3 years ago

167÷2=83.5 how to solve

gavmur [86]

Step-by-step explanation:

162/2 (the same as 162÷2) =83.5

83.5+83.5=162

that was two times to add so we know for sure that 162/2=83.5. Theres no special way to solve it since its just dived by <em>two</em>. Its just 162÷2=83.5

Hope this helps.

3 0

3 years ago

Read 2 more answers

-6a-4= -4 (1+7a) Solve for a.

soldi70 [24.7K]

Answer:

$a = 0$

Step-by-step explanation:

On the right side of the = multiply -4 through

$- 6a - 4 = - 4 - 28a$

add 28a and add 4 to both sides

$28a - 6a = 4 - 4$

$22a = 0$

divide both sides by 22

$a = 0$

6 0

2 years ago

Read 2 more answers

Find an equation of the tangent plane to the given parametric surface at the specified point.

Neko [114]

Answer:

Equation of tangent plane to given parametric equation is:

$\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

Step-by-step explanation:

Given equation

$r(u, v)=u cos (v)\hat{i}+u sin (v)\hat{j}+v\hat{k}$ ---(1)

Normal vector tangent to plane is:

$\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}$

$\frac{\partial r}{\partial u} =cos(v)\hat{i}+sin(v)\hat{j}\\\frac{\partial r}{\partial v}=-usin(v)\hat{i}+u cos(v)\hat{j}+\hat{k}$

Normal vector tangent to plane is given by:

$r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]$

Expanding with first row

$\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\$

at u=5, v =π/3

$=\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k}$ ---(2)

at u=5, v =π/3 (1) becomes,

$r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=\frac{5}{2}\hat{i}+(\frac{5\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

From above eq coordinates of r₀ can be found as:

$r_{o}=(\frac{5}{2},\frac{5\sqrt{3}}{2},\frac{\pi}{3})$

From (2) coordinates of normal vector can be found as

$n=(\frac{\sqrt{3} }{2},-\frac{1}{2},1)$

Equation of tangent line can be found as:

$(\hat{r}-\hat{r_{o}}).\hat{n}=0\\((x-\frac{5}{2})\hat{i}+(y-\frac{5\sqrt{3}}{2})\hat{j}+(z-\frac{\pi}{3})\hat{k})(\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k})=0\\\frac{\sqrt{3}}{2}x-\frac{5\sqrt{3}}{4}-\frac{1}{2}y+\frac{5\sqrt{3}}{4}+z-\frac{\pi}{3}=0\\\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

5 0

3 years ago

write the equation in slope-intercept form with y intercept of −3 and an x intercept of −4.5.plz help thanks!

Mashcka [7]

The equation of the line is y = -2/3x - 3.

To find this, we first need to turn the intercepts into ordered pairs.

x intercept: (-4.5, 0)

y intercept: (0, -3)

Now we can use these two points and the slope equation to find slope.

m = (y2 - y1)/(x2 - x1)

m = (0 - -3)/(-4.5 - 0)

m = 3/-4.5

m = -2/3

Now that we have the slope, we can use slope intercept form to find the intercept.

y = mx + b

-3 = 2/3(0) + b

-3 = 0 + b

-3 = b

Which allows us to model the equation as y = -2/3x - 3

4 0

3 years ago