How much water should be added to one liter of pure ammonia to make a mixture of 50% ammonia
1 answer:
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Answer:
Step-by-step explanation:
Below is the pic of how this would be set up in order to determine what it is you are looking for. The angle is set in QI, and since csc A is the reciprocal of sin, the ratio is hypotenuse over side opposite. Solve for the missing side using Pythagorean's Theorem:
and
1369 = 144 + b² and
1225 = b² so
b = 35
The sec ratio is the reciprocal of cos, so if cos is adjacent over hypotenuse, the sec is hypotenuse over adjacent, which is 37/35
Answer:
Step-by-step explanation:
What I did was
then I did
and I'm hoping 150 is the answer. HOPE THIS HELPED
This should have been worth more points, but anyways, here are the answers. Please give thanks :)
1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X
5.) Y = </span>X +6 <span>
6.) Y = 5 -3X
7.) Y = 2 +</span>
<span>X
8.) </span>Y =
X - 3<span>
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y = 1 - 5X
11.) Y = 2 - </span>
<span>X
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span>
<span> -2X
15.) Y = 2 +</span><span>X
16.) Y = 2 +</span><span>X
17.) Y = 1 - 5X
18.) Y = </span>[<span>tex] \frac{3}{4} [/tex]</span>X + 2
1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X
5.) Y = </span>X +6 <span>
6.) Y = 5 -3X
7.) Y = 2 +</span>
8.) </span>Y =
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y = 1 - 5X
11.) Y = 2 - </span>
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span>
15.) Y = 2 +</span>
16.) Y = 2 +</span>
17.) Y = 1 - 5X
18.) Y = </span>[<span>tex] \frac{3}{4} [/tex]</span>X + 2