Standard Form looks like this:
Also, A cannot be negative and there are no fractions in Standard Form.
Now that we know the rules of Standard Form, let's get x and y on one side.
-2/3y = 2 + 8/15x
Subtract 8/15x from both sides.
-8/15x - 2/3y = 2
Multiply 2/3 by 5/5 to get a common denominator.
-8/15x - 10/15y = 2
Multiply everything by 15 to rid of the fractions.
-8x - 10y = 30
Multiply everything by -1 to make A positive.
8x + 10y = -30
8x + 10y = -30
Answer: 1, 1, 6, 6, 6, 8, 8
Step-by-step explanation:
Median = 6
Mode = 6
please give me a brainliest answer
Im pretty sure that the answer is
−1234564
If the soda can is a cylinder, which is most likely, than that means we need to find the height of the cone. The formula for volume of a cylinder is V= пr^2h (look at the pic for clearer formula) and we know the diameter of the soda can is 6, we know the radius is 3 because diameter is a line reaching from one point of the circle to the other. Radius is a line reaching from the center of the circle to the outside as shown in the image. We divide pi (you can put in the calculator 3.14) from 21, then we get 6.688 (if we round up) and then you must look at the formula now
it looks like
6.688=r^2h
that means we must find 3^2
that basically means 3x3 which is 9
then you have to divide that from 6.688
then you get 0.743
that is your height.
now we must find the volume of the cone. The formula for that is
V=пr^2(h/3)
now lets plug in our info
V=(3.14)(9)(0.743/3)
you get 6.999
Answer:
The most that a bag can weigh and not need to be repackaged is 15.355 ounces.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Bags in the upper 4% are too heavy and must be repackaged. What is the most that a bag can weigh and not need to be repackaged?
Bags in the upper 4% have a pvalue of 1-0.04 = 0.96. So the most that a bag can weight and not need to be repackaged is the value of X when Z has a pvalue of 0.9599. So this is X when 
The most that a bag can weigh and not need to be repackaged is 15.355 ounces.
