System of Linear Equations entered :
[1] 5x - 6y = 7
[2] 6x - 7y = 8
Graphic Representation of the Equations :
-6y + 5x = 7 -7y + 6x = 8
Solve equation [2] for the variable x
[2] 6x = 7y + 8
[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]
[1] 5•(7y/6+4/3) - 6y = 7
[1] - y/6 = 1/3
[1] - y = 2
// Solve equation [1] for the variable y
[1] y = - 2
// By now we know this much :
x = 7y/6+4/3
y = -2
// Use the y value to solve for x
x = (7/6)(-2)+4/3 = -1
Let x be the number of days.
Daily pass:
65x + 30x
95x
Season pass:
400 + 30x
95x > 400 + 30x
65x > 400
x > 6.15
The number of days can't be 6.15, so you must round. You can't go down because then the price will be more expensive, so you have to round up.
It would take 7 days until the season pass is less expensive than the daily pass.
----------------------
You can check this by plugging in the x.
95x > 400 + 30x
95(7) > 400 + 30(7)
665 > 400 + 210
665 > 600
The daily pass is more expensive than the season pass.
the answer it four and one sixths
Answer:
D 36
Step-by-step explanation:
<em>Write the information algebraically</em>
c = 3a
c + a = 48
c = children, a = adults
<em>In the second sentence (in bold), we can replace c with 3a</em>
c + a = 48 → 3a + a = 48
<em>Simplify</em>
3a + a = 48 → 4a = 48 → a = 12 (divide both sides by 4)
<em>We can then substitute or plug in a = 12 into the original equation:</em>
c + a = 48 → c + 12 = 48 → c = 36 (subtract 12 from both sides)
<h3>There are 36 children</h3>
The required diameter of dwarf planet is 
.
<h3>What is a statement?</h3>
A statement is a declarative sentence that is either true or false but not both. A statement is sometimes called a proposition. The key is that there must be no ambiguity. To be a statement, a sentence must be true or false, and it cannot be both.
Given:
The given statement is the diameter of 3 planet is
planet A= 
= 1000000000m
planet B=
=10000000m
planet C= 
=100000000m
According to given question we have
A dwarf planet is discovered with a radius is 1/100 times of radius of planet C.
Radius of planet C =100000000/2= 50000000m
Radius of dwarf planet = 1/100 times of radius of planet C.
Radius of dwarf planet = 1/100 * 50000000m
Radius of dwarf planet = 500000 m=
Diameter of dwarf planet =2*500000 m=1000000 m=
Therefore, the required diameter of dwarf planet is .
Learn more details about statement here:
brainly.com/question/2285414
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