Answer:
P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.
Step-by-step explanation:
P and Q are the intersection points of
x-y+1 = 0 and the circle x^2 + y^2 = 25
sub y = x+1 into the circle
x^2 + (x+1)^2 = 25
x^2 + x^2 + 2x + 1 - 25 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = 3 or x = -4
y = 4 or y = -3
so P(3,4) and Q(-4,3) are our two points
Height of triangle.
h = |0 - 0 + 1|/√2 = 1/√2
PQ = √( (-7)^2 + 1^2) = √50 = 5√2
area POQ = (1/2)(1/√2)(5√2) = 5/2 square units
hope this helped
D
Because it is one of the parent functions
The diagram of each shape are shown below
The shapes that have two consecutive angles of 90° is square and rectangle, so the correct option is option A
I think the answer is Letter C - 0.032.
Given: p - 0.1; n - 90
Required: standard deviation of the sample proportion
Solution: To get the standard deviation of the sample proportion, we will use this formula - std = √p (1 - p) / n Replace the variables with the given values, then simplify.
std = √0.1 (1 - 0.1) / 90
std = √0.09 / 90
std = √0.001
std = 0.032
