Answer:
Step-by-step explanation:
8p+3f=10.39
5p+4f=10.51
subtract
3p-f=-0.12
f=3p+0.12
8p+3(3p+0.12)=10.39
17p=10.39-0.36
17p=10.03
p=10.03/17=0.59
f=3×0.59+0.12=1.77+0.12=1.89 $
or 40 p+15f-40p-32f=51.95-84.08
-17f=-32.13
f=1.89 $
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
B is the answer because yes
Answer:
A) Both estimates are slightly larger, so it is reasonable.
Step-by-step explanation:
Since 1/2 = 5/10
And 1/5 = 8/40
<u>Both estimates are larger</u>