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Bas_tet [7]
3 years ago
5

What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix?

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0
We're given focus =(−2, 4) and directrix Y = 6 We start with this equation:
(x- h)^2 = 4p * (y -k)

The "x" value of the focus = the "x" value of the directrix = -2 (which also = "h")
The "y" value (or "k") lies between the focus "y" value and the directrix "y" value k = (4 + 6 / 2) = 5
p = one half the distance from directrix to focus = .5 * (6 -4) = 1
Now we enter these numbers into:(x- h)^2 = 4p * (y -k)(x --2)^2 = 4*1 * (y -5)(x +2)^2 = 4y -20x^2 + 4 x + 4 = 4y - 204y = x^2 + 4 x + 24 y = x^2/4 + x + 6
Source:http://www.1728.org/quadr4.htm

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3 years ago
What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
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Answer:

\boxed{m = - \frac{33}{14} }

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Step-by-step explanation:

Use the form below

\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}

Where

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So, the slope is

(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1

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m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }

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Happy to help:)

7 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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