Answer:
The fourth one.
Step-by-step explanation:
I am pretty sure.
The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:

![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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Answer:
c = 24
Step-by-step explanation:
1/3c - 7 = 1
add 7 to both sides
1/3c = 8
now multiply 3 to both sides
c = 24
Answer:
Step-by-step explanation:

All the variables on the right are being multiplied together then the whole mess is being divided by 2. Let's get rid of the 2 first. The undoing of division is multiplication, so we will begin by multiplying both sides by 2 to get

Next we will move the m. The undoing of multiplication is division. So we divide both sides by m to get

The undoing of a square is to take the square root, so we will do that to both sides giving us, finally
Answer:
The answers are as follows:
5. c
6. b
7. not sure, sorry
8. b
Step-by-step explanation: