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GarryVolchara [31]
3 years ago
8

A culture of bacteria has an initial population of 8300 bacteria and doubles every 10 hours. Using the formula Pt=P0*2^t/d , whe

re Pt is the population after t hours, P0 is the initial population, t is the time in hours and d is the doubling time, what is the population of bacteria in the culture after 3 hours, to the nearest whole number?
Mathematics
1 answer:
tatiyna3 years ago
8 0

Answer:

10,219 bacteria

Step-by-step explanation:

In this question, we are asked to calculate the population of bacteria in a culture given the formula for the population increase.

From the question, we know the formula to use is

Pt=Po*2^t/d

From the parameters in the question, we identify that Pt is ?, Po is 8300 bacteria , t is 3 hours and d is 10 hours which is the doubling time. Inserting these figures we have;

Pt = 8300 * 2^(3/10)

Pt = 8300 * 2^0.3

Pt = 10,218.5

Pt = 10,219 bacteria to the nearest whole number

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40/x=2/3

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A random sample of 42 college graduates who worked during their program revealed that a student spent an average 5.5 years on th
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Answer:

5.5-2.701\frac{1.1}{\sqrt{42}}=5.04    

5.5+2.701\frac{1.1}{\sqrt{42}}=5.96    

So on this case the 99% confidence interval would be given by (5.04;5.96)

And the best option would be:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X=5.5 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=1.1 represent the sample standard deviation

n=42 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,41)".And we see that t_{\alpha/2}=2.701

Now we have everything in order to replace into formula (1):

5.5-2.701\frac{1.1}{\sqrt{42}}=5.04    

5.5+2.701\frac{1.1}{\sqrt{42}}=5.96    

So on this case the 99% confidence interval would be given by (5.04;5.96)

And the best option would be:

a. 5.04 and 5.96

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