Answer:
See proof below
Step-by-step explanation:
We have to verify that if we substitute 
in the equation 
the equality is true.
Let's substitute first in the right hand side:
Now we use the distributive laws. Also, note that 
(this also works when the power is n-2).
then the sequence solves the recurrence relation.
<span>-8 < x -3 < 1
we have two inequations:
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
* x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
Either you can use distributive property or you can add up the numbers in the brackets.
Hopefully that helped! :)
