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3 years ago

What two numbers add to 2500

Mathematics

2 answers:

Arturiano [62]3 years ago

8 0

1300 and 1200add up to 2500

elixir [45]3 years ago

8 0

1300 and 1200 add to 2500

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Describe 58 as a sum of tens and ones

Thepotemich [5.8K]

Answer:

5 tens and 8 ones gives 58

Step-by-step explanation:

We have to describe 58 as a sum of tens and ones

We know that first digit from the right is the ones place

Second digit is the tens place

Hence, 5 tens and 8 ones gives 58

Also, we can see that

10+10+10+10+10=50 (5 tens)

and 1+1+1+1+1+1+1+1=8 (8 ones)

on adding both we get 58

Hence, 5 tens and 8 ones gives 58

4 0

3 years ago

Read 2 more answers

Q no 13 and 14 answer

GalinKa [24]

Answer:

<h2>Question 13 : x = 62°</h2>

<h2>Question 14 : x = 2</h2>

Step-by-step explanation:

Question 13

The diagram in question 13 is a triangle.

The sum of interior angles of a triangle is equal to 180°

To solve for x ;

$x + 69 + 49 = 180 \\ x + 118 = 180 \\ x = 180 - 118 \\ x = 62$

Question 14

(: represents ratio or /)

x/9 = 18/81

Cross Multiply

81x = 18×9

81x = 162

Divide both sides of the equation by 81

81x/81 = 162/81

x = 2

7 0

3 years ago

Please help sadmasdasfasfsag

Vesnalui [34]

Answer: 1- subtract 25 from 62, that’s your x

2- add 19 to 46, that’s your y

3- subtract 56 from 74, that’s your b

Step-by-step explanation:

7 0

3 years ago

Which theorem can be used to prove that the triangles in the figure below are congruent?

Minchanka [31]

Answer:

There are 5 theorem to prove the triangles are congruent. They are:

6 0

3 years ago

Show that (f o g)(x) = (g o f)(x) = x

cluponka [151]

Answer:

$- \frac{2[1 - x]}{3} = g[f(x)] \\ \\ \frac{3x}{2 - x} = f[g(x)]$

Step-by-step explanation:

They are not.

For the g[f(x)] function, you substitute ³/ₓ ₋ ₁ from the f(x) function in for x in the g(x) function to get this:

$\frac{2}{ \frac{3}{x - 1}}$

Then, you bring x - 1 to the top while changing the expression to its conjugate [same expressions with opposite symbols]:

$- \frac{2[1 - x]}{3}$

You could also do this [attaching another negative would make that positive].

For the f[g(x)] function, ²/ₓ from the g(x) function for x in the f(x) function to get this:

$\frac{3}{ \frac{2}{x} - 1}$

Now, if you look closely, ²/ₓ is written as 2x⁻¹, and according to the Negative Exponential Rule, you bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM NEGATIVE TO POSITIVE:

$\frac{3x}{2 - x}$

When this happens, x leaves the two and gets attached to the three, and 1 gets an x attached to it.

I am joyous to assist you anytime.

6 0

3 years ago