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Crazy boy [7]
3 years ago
15

Answer each question with a fraction.

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

The average speed is \frac{3}{35}\frac{ft}{min}

Step-by-step explanation:

we know that

To find out the average speed divide the distance by the time

Let

s -----> average speed

d -----> the distance in feet

t ----> the time in minutes

s=\frac{d}{t}

we have

d=6\ ft

t=70\ min

substitute

s=\frac{6}{70}\frac{ft}{min}

Simplify

s=\frac{3}{35}\frac{ft}{min}

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I need help because I don’t know what they are asking
Mashutka [201]

Answer:

  16x -2

Step-by-step explanation:

You know how to compute the perimeter of a rectangle of length L and width W:

  P = 2(L+W)

Here, you're asked to use the given algebraic expressions for length and width and simplify the result of putting those in the perimeter formula.

  P = 2((5x-2) +(3x+1))

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3 years ago
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a common what? denominator?


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kykrilka [37]
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3 years ago
Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra
Nana76 [90]

The length of BC is 4 \sqrt{5}.

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

<u>Leg rule of geometric mean theorem:</u>

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

\Rightarrow  16\times 5 = x\times x

\Rightarrow  80= x^2

\Rightarrow  16\times 5= x^2

Taking square root on both sides.

\Rightarrow  \sqrt{16\times 5} = \sqrt{x^2}

\Rightarrow  \sqrt{4^2\times 5} = \sqrt{x^2}

square and square roots get canceled, we get

\Rightarrow  4\sqrt{ 5} = x

The length of BC is 4 \sqrt{5}.

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